How much energy is released by the fusion of four hydrogen atoms to form a helium nucleus (in $MeV$)?

  • A
    $26.7$
  • B
    $13.6$
  • C
    $6.7$
  • D
    $3.4$

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Similar Questions

$_{1}^{2} H + _{1}^{3} H \to _{2}^{4} He + _{0}^{1} n$
If the binding energies of $_{1}^{2} H, _{1}^{3} H$ and $_{2}^{4} He$ are $a, b$ and $c$ (in $MeV$) respectively, then the energy released in the reaction is:

Energy released in the fission of a single ${ }_{92} U^{235}$ nucleus is $200 \ MeV$. The fission rate of a ${ }_{92} U^{235}$ fuelled reactor operating at a power level of $32 \ kW$ is:

When $_3^7Li$ nuclei are bombarded by protons, and the resultant nuclei are $_4^8Be$, the emitted particles will be

The $Q$ value of a nuclear reaction $A+b \rightarrow C+d$ is defined by $Q=\left[m_{A}+m_{b}-m_{C}-m_{d}\right] c^{2}$ where the masses refer to the respective nuclei. Determine from the given data the $Q$ value of the following reactions and state whether the reactions are exothermic or endothermic.
$(i) \;_{1}^{1} H+_{1}^{3} H \rightarrow_{1}^{2} H+_{1}^{2} H$
$(ii)\;_{6}^{12} C+_{6}^{12} C \rightarrow_{10}^{20} N e+_{2}^{4} H e$
Atomic masses are given to be:
$m(_{1}^{1}H) = 1.007825 \; u$
$m(_{1}^{2}H) = 2.014102 \; u$
$m(_{1}^{3}H) = 3.016049 \; u$
$m(_{6}^{12}C) = 12.000000 \; u$
$m(_{10}^{20}Ne) = 19.992439 \; u$
$m(_{2}^{4}He) = 4.002603 \; u$

What are control rods in a nuclear reactor?

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